(x+2)(x+3)=(x+5)(x+1)

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Solution for (x+2)(x+3)=(x+5)(x+1) equation: 



(x+2)(x+3)=(x+5)(x+1)

We move all terms to the left:

(x+2)(x+3)-((x+5)(x+1))=0

We multiply parentheses ..

(+x^2+3x+2x+6)-((x+5)(x+1))=0



We calculate terms in parentheses: -((x+5)(x+1)), so:

(x+5)(x+1)

We multiply parentheses ..

(+x^2+x+5x+5)

We get rid of parentheses

x^2+x+5x+5

We add all the numbers together, and all the variables

x^2+6x+5

Back to the equation:

-(x^2+6x+5)



We get rid of parentheses

x^2-x^2+3x+2x-6x+6-5=0

We add all the numbers together, and all the variables

-1x+1=0

We move all terms containing x to the left, all other terms to the right

-x=-1

x=-1/-1

x=1

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