(x+2)(x+3)=(x-1)(x-6)

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Solution for (x+2)(x+3)=(x-1)(x-6) equation: 



(x+2)(x+3)=(x-1)(x-6)

We move all terms to the left:

(x+2)(x+3)-((x-1)(x-6))=0

We multiply parentheses ..

(+x^2+3x+2x+6)-((x-1)(x-6))=0



We calculate terms in parentheses: -((x-1)(x-6)), so:

(x-1)(x-6)

We multiply parentheses ..

(+x^2-6x-1x+6)

We get rid of parentheses

x^2-6x-1x+6

We add all the numbers together, and all the variables

x^2-7x+6

Back to the equation:

-(x^2-7x+6)



We get rid of parentheses

x^2-x^2+3x+2x+7x+6-6=0

We add all the numbers together, and all the variables

12x=0

x=0/12

x=0

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