(x+2)(x+3)=x

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Solution for (x+2)(x+3)=x equation: 



(x+2)(x+3)=x

We move all terms to the left:

(x+2)(x+3)-(x)=0

We add all the numbers together, and all the variables

-1x+(x+2)(x+3)=0

We multiply parentheses ..

(+x^2+3x+2x+6)-1x=0

We get rid of parentheses

x^2+3x+2x-1x+6=0

We add all the numbers together, and all the variables

x^2+4x+6=0

a = 1; b = 4; c = +6;
Δ = b2-4ac
Δ = 42-4·1·6
Δ = -8
Delta is less than zero, so there is no solution for the equation

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