(x+2)(x+3)=x(x+4)

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Solution for (x+2)(x+3)=x(x+4) equation: 



(x+2)(x+3)=x(x+4)

We move all terms to the left:

(x+2)(x+3)-(x(x+4))=0

We multiply parentheses ..

(+x^2+3x+2x+6)-(x(x+4))=0



We calculate terms in parentheses: -(x(x+4)), so:

x(x+4)

We multiply parentheses

x^2+4x

Back to the equation:

-(x^2+4x)



We get rid of parentheses

x^2-x^2+3x+2x-4x+6=0

We add all the numbers together, and all the variables

x+6=0

We move all terms containing x to the left, all other terms to the right

x=-6

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