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(x+2)(x+3)=x2+5x+6
We move all terms to the left:
(x+2)(x+3)-(x2+5x+6)=0
We add all the numbers together, and all the variables
-(+x^2+5x+6)+(x+2)(x+3)=0
We get rid of parentheses
-x^2-5x+(x+2)(x+3)-6=0
We multiply parentheses ..
-x^2+(+x^2+3x+2x+6)-5x-6=0
We add all the numbers together, and all the variables
-1x^2+(+x^2+3x+2x+6)-5x-6=0
We get rid of parentheses
-1x^2+x^2+3x+2x-5x+6-6=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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