(x+2)(x+4)=3x+2(x+2)

Solution for (x+2)(x+4)=3x+2(x+2) equation:

(x+2)(x+4)=3x+2(x+2)

We move all terms to the left:

(x+2)(x+4)-(3x+2(x+2))=0

We multiply parentheses ..

(+x^2+4x+2x+8)-(3x+2(x+2))=0


We calculate terms in parentheses: -(3x+2(x+2)), so:

3x+2(x+2)

We multiply parentheses

3x+2x+4

We add all the numbers together, and all the variables

5x+4

Back to the equation:

-(5x+4)


We get rid of parentheses

x^2+4x+2x-5x+8-4=0

We add all the numbers together, and all the variables

x^2+x+4=0

a = 1; b = 1; c = +4;
Δ = b2-4ac
Δ = 12-4·1·4
Δ = -15
Delta is less than zero, so there is no solution for the equation