(x+2)(x+8)=(x-10)(x+2)

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Solution for (x+2)(x+8)=(x-10)(x+2) equation: 



(x+2)(x+8)=(x-10)(x+2)

We move all terms to the left:

(x+2)(x+8)-((x-10)(x+2))=0

We multiply parentheses ..

(+x^2+8x+2x+16)-((x-10)(x+2))=0



We calculate terms in parentheses: -((x-10)(x+2)), so:

(x-10)(x+2)

We multiply parentheses ..

(+x^2+2x-10x-20)

We get rid of parentheses

x^2+2x-10x-20

We add all the numbers together, and all the variables

x^2-8x-20

Back to the equation:

-(x^2-8x-20)



We get rid of parentheses

x^2-x^2+8x+2x+8x+16+20=0

We add all the numbers together, and all the variables

18x+36=0

We move all terms containing x to the left, all other terms to the right

18x=-36

x=-36/18

x=-2

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