(x+2)(x-1)=(x+1)(x+6)

Solution for (x+2)(x-1)=(x+1)(x+6) equation:

(x+2)(x-1)=(x+1)(x+6)

We move all terms to the left:

(x+2)(x-1)-((x+1)(x+6))=0

We multiply parentheses ..

(+x^2-1x+2x-2)-((x+1)(x+6))=0


We calculate terms in parentheses: -((x+1)(x+6)), so:

(x+1)(x+6)

We multiply parentheses ..

(+x^2+6x+x+6)

We get rid of parentheses

x^2+6x+x+6

We add all the numbers together, and all the variables

x^2+7x+6

Back to the equation:

-(x^2+7x+6)


We get rid of parentheses

x^2-x^2-1x+2x-7x-2-6=0

We add all the numbers together, and all the variables

-6x-8=0

We move all terms containing x to the left, all other terms to the right

-6x=8

x=8/-6

x=-1+1/3