(x+2)(x-1)=(x+5)(x-2)

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Solution for (x+2)(x-1)=(x+5)(x-2) equation: 



(x+2)(x-1)=(x+5)(x-2)

We move all terms to the left:

(x+2)(x-1)-((x+5)(x-2))=0

We multiply parentheses ..

(+x^2-1x+2x-2)-((x+5)(x-2))=0



We calculate terms in parentheses: -((x+5)(x-2)), so:

(x+5)(x-2)

We multiply parentheses ..

(+x^2-2x+5x-10)

We get rid of parentheses

x^2-2x+5x-10

We add all the numbers together, and all the variables

x^2+3x-10

Back to the equation:

-(x^2+3x-10)



We get rid of parentheses

x^2-x^2-1x+2x-3x-2+10=0

We add all the numbers together, and all the variables

-2x+8=0

We move all terms containing x to the left, all other terms to the right

-2x=-8

x=-8/-2

x=+4

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