(x+2)(x-12)=0

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Solution for (x+2)(x-12)=0 equation:


Simplifying
(x + 2)(x + -12) = 0

Reorder the terms:
(2 + x)(x + -12) = 0

Reorder the terms:
(2 + x)(-12 + x) = 0

Multiply (2 + x) * (-12 + x)
(2(-12 + x) + x(-12 + x)) = 0
((-12 * 2 + x * 2) + x(-12 + x)) = 0
((-24 + 2x) + x(-12 + x)) = 0
(-24 + 2x + (-12 * x + x * x)) = 0
(-24 + 2x + (-12x + x2)) = 0

Combine like terms: 2x + -12x = -10x
(-24 + -10x + x2) = 0

Solving
-24 + -10x + x2 = 0

Solving for variable 'x'.

Factor a trinomial.
(-2 + -1x)(12 + -1x) = 0

Subproblem 1

Set the factor '(-2 + -1x)' equal to zero and attempt to solve: Simplifying -2 + -1x = 0 Solving -2 + -1x = 0 Move all terms containing x to the left, all other terms to the right. Add '2' to each side of the equation. -2 + 2 + -1x = 0 + 2 Combine like terms: -2 + 2 = 0 0 + -1x = 0 + 2 -1x = 0 + 2 Combine like terms: 0 + 2 = 2 -1x = 2 Divide each side by '-1'. x = -2 Simplifying x = -2

Subproblem 2

Set the factor '(12 + -1x)' equal to zero and attempt to solve: Simplifying 12 + -1x = 0 Solving 12 + -1x = 0 Move all terms containing x to the left, all other terms to the right. Add '-12' to each side of the equation. 12 + -12 + -1x = 0 + -12 Combine like terms: 12 + -12 = 0 0 + -1x = 0 + -12 -1x = 0 + -12 Combine like terms: 0 + -12 = -12 -1x = -12 Divide each side by '-1'. x = 12 Simplifying x = 12

Solution

x = {-2, 12}

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