(x+2)(x-2)(4x+1)=0

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Solution for (x+2)(x-2)(4x+1)=0 equation: 


Simplifying
(x + 2)(x + -2)(4x + 1) = 0

Reorder the terms:
(2 + x)(x + -2)(4x + 1) = 0

Reorder the terms:
(2 + x)(-2 + x)(4x + 1) = 0

Reorder the terms:
(2 + x)(-2 + x)(1 + 4x) = 0

Multiply (2 + x) * (-2 + x)
(2(-2 + x) + x(-2 + x))(1 + 4x) = 0
((-2 * 2 + x * 2) + x(-2 + x))(1 + 4x) = 0
((-4 + 2x) + x(-2 + x))(1 + 4x) = 0
(-4 + 2x + (-2 * x + x * x))(1 + 4x) = 0
(-4 + 2x + (-2x + x2))(1 + 4x) = 0

Combine like terms: 2x + -2x = 0
(-4 + 0 + x2)(1 + 4x) = 0
(-4 + x2)(1 + 4x) = 0

Multiply (-4 + x2) * (1 + 4x)
(-4(1 + 4x) + x2(1 + 4x)) = 0
((1 * -4 + 4x * -4) + x2(1 + 4x)) = 0
((-4 + -16x) + x2(1 + 4x)) = 0
(-4 + -16x + (1 * x2 + 4x * x2)) = 0
(-4 + -16x + (1x2 + 4x3)) = 0
(-4 + -16x + 1x2 + 4x3) = 0

Solving
-4 + -16x + 1x2 + 4x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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