(x+2)(x-2)(x+3)(x-3)=

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Solution for (x+2)(x-2)(x+3)(x-3)= equation:


Simplifying
(x + 2)(x + -2)(x + 3)(x + -3) = 0

Reorder the terms:
(2 + x)(x + -2)(x + 3)(x + -3) = 0

Reorder the terms:
(2 + x)(-2 + x)(x + 3)(x + -3) = 0

Reorder the terms:
(2 + x)(-2 + x)(3 + x)(x + -3) = 0

Reorder the terms:
(2 + x)(-2 + x)(3 + x)(-3 + x) = 0

Multiply (2 + x) * (-2 + x)
(2(-2 + x) + x(-2 + x))(3 + x)(-3 + x) = 0
((-2 * 2 + x * 2) + x(-2 + x))(3 + x)(-3 + x) = 0
((-4 + 2x) + x(-2 + x))(3 + x)(-3 + x) = 0
(-4 + 2x + (-2 * x + x * x))(3 + x)(-3 + x) = 0
(-4 + 2x + (-2x + x2))(3 + x)(-3 + x) = 0

Combine like terms: 2x + -2x = 0
(-4 + 0 + x2)(3 + x)(-3 + x) = 0
(-4 + x2)(3 + x)(-3 + x) = 0

Multiply (-4 + x2) * (3 + x)
(-4(3 + x) + x2(3 + x))(-3 + x) = 0
((3 * -4 + x * -4) + x2(3 + x))(-3 + x) = 0
((-12 + -4x) + x2(3 + x))(-3 + x) = 0
(-12 + -4x + (3 * x2 + x * x2))(-3 + x) = 0
(-12 + -4x + (3x2 + x3))(-3 + x) = 0
(-12 + -4x + 3x2 + x3)(-3 + x) = 0

Multiply (-12 + -4x + 3x2 + x3) * (-3 + x)
(-12(-3 + x) + -4x * (-3 + x) + 3x2 * (-3 + x) + x3(-3 + x)) = 0
((-3 * -12 + x * -12) + -4x * (-3 + x) + 3x2 * (-3 + x) + x3(-3 + x)) = 0
((36 + -12x) + -4x * (-3 + x) + 3x2 * (-3 + x) + x3(-3 + x)) = 0
(36 + -12x + (-3 * -4x + x * -4x) + 3x2 * (-3 + x) + x3(-3 + x)) = 0
(36 + -12x + (12x + -4x2) + 3x2 * (-3 + x) + x3(-3 + x)) = 0
(36 + -12x + 12x + -4x2 + (-3 * 3x2 + x * 3x2) + x3(-3 + x)) = 0
(36 + -12x + 12x + -4x2 + (-9x2 + 3x3) + x3(-3 + x)) = 0
(36 + -12x + 12x + -4x2 + -9x2 + 3x3 + (-3 * x3 + x * x3)) = 0
(36 + -12x + 12x + -4x2 + -9x2 + 3x3 + (-3x3 + x4)) = 0

Combine like terms: -12x + 12x = 0
(36 + 0 + -4x2 + -9x2 + 3x3 + -3x3 + x4) = 0
(36 + -4x2 + -9x2 + 3x3 + -3x3 + x4) = 0

Combine like terms: -4x2 + -9x2 = -13x2
(36 + -13x2 + 3x3 + -3x3 + x4) = 0

Combine like terms: 3x3 + -3x3 = 0
(36 + -13x2 + 0 + x4) = 0
(36 + -13x2 + x4) = 0

Solving
36 + -13x2 + x4 = 0

Solving for variable 'x'.

Factor a trinomial.
(4 + -1x2)(9 + -1x2) = 0

Factor a difference between two squares.
((2 + x)(2 + -1x))(9 + -1x2) = 0

Factor a difference between two squares.
((3 + x)(3 + -1x))(2 + x)(2 + -1x) = 0

Subproblem 1

Set the factor '(2 + x)' equal to zero and attempt to solve: Simplifying 2 + x = 0 Solving 2 + x = 0 Move all terms containing x to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + x = 0 + -2 Combine like terms: 2 + -2 = 0 0 + x = 0 + -2 x = 0 + -2 Combine like terms: 0 + -2 = -2 x = -2 Simplifying x = -2

Subproblem 2

Set the factor '(2 + -1x)' equal to zero and attempt to solve: Simplifying 2 + -1x = 0 Solving 2 + -1x = 0 Move all terms containing x to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + -1x = 0 + -2 Combine like terms: 2 + -2 = 0 0 + -1x = 0 + -2 -1x = 0 + -2 Combine like terms: 0 + -2 = -2 -1x = -2 Divide each side by '-1'. x = 2 Simplifying x = 2

Subproblem 3

Set the factor '(3 + x)' equal to zero and attempt to solve: Simplifying 3 + x = 0 Solving 3 + x = 0 Move all terms containing x to the left, all other terms to the right. Add '-3' to each side of the equation. 3 + -3 + x = 0 + -3 Combine like terms: 3 + -3 = 0 0 + x = 0 + -3 x = 0 + -3 Combine like terms: 0 + -3 = -3 x = -3 Simplifying x = -3

Subproblem 4

Set the factor '(3 + -1x)' equal to zero and attempt to solve: Simplifying 3 + -1x = 0 Solving 3 + -1x = 0 Move all terms containing x to the left, all other terms to the right. Add '-3' to each side of the equation. 3 + -3 + -1x = 0 + -3 Combine like terms: 3 + -3 = 0 0 + -1x = 0 + -3 -1x = 0 + -3 Combine like terms: 0 + -3 = -3 -1x = -3 Divide each side by '-1'. x = 3 Simplifying x = 3

Solution

x = {-2, 2, -3, 3}

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