(x+2)(x-2)-5=0

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Solution for (x+2)(x-2)-5=0 equation:


Simplifying
(x + 2)(x + -2) + -5 = 0

Reorder the terms:
(2 + x)(x + -2) + -5 = 0

Reorder the terms:
(2 + x)(-2 + x) + -5 = 0

Multiply (2 + x) * (-2 + x)
(2(-2 + x) + x(-2 + x)) + -5 = 0
((-2 * 2 + x * 2) + x(-2 + x)) + -5 = 0
((-4 + 2x) + x(-2 + x)) + -5 = 0
(-4 + 2x + (-2 * x + x * x)) + -5 = 0
(-4 + 2x + (-2x + x2)) + -5 = 0

Combine like terms: 2x + -2x = 0
(-4 + 0 + x2) + -5 = 0
(-4 + x2) + -5 = 0

Reorder the terms:
-4 + -5 + x2 = 0

Combine like terms: -4 + -5 = -9
-9 + x2 = 0

Solving
-9 + x2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '9' to each side of the equation.
-9 + 9 + x2 = 0 + 9

Combine like terms: -9 + 9 = 0
0 + x2 = 0 + 9
x2 = 0 + 9

Combine like terms: 0 + 9 = 9
x2 = 9

Simplifying
x2 = 9

Take the square root of each side:
x = {-3, 3}

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