(x+2)(x-4)-2(x-4)=x(x-4)

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Solution for (x+2)(x-4)-2(x-4)=x(x-4) equation: 



(x+2)(x-4)-2(x-4)=x(x-4)

We move all terms to the left:

(x+2)(x-4)-2(x-4)-(x(x-4))=0

We multiply parentheses

(x+2)(x-4)-2x-(x(x-4))+8=0

We multiply parentheses ..

(+x^2-4x+2x-8)-2x-(x(x-4))+8=0



We calculate terms in parentheses: -(x(x-4)), so:

x(x-4)

We multiply parentheses

x^2-4x

Back to the equation:

-(x^2-4x)



We get rid of parentheses

x^2-x^2-4x+2x-2x+4x-8+8=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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