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(x+2)(x-4)-2(x-4)=x(x-4)
We move all terms to the left:
(x+2)(x-4)-2(x-4)-(x(x-4))=0
We multiply parentheses
(x+2)(x-4)-2x-(x(x-4))+8=0
We multiply parentheses ..
(+x^2-4x+2x-8)-2x-(x(x-4))+8=0
We calculate terms in parentheses: -(x(x-4)), so:We get rid of parentheses
x(x-4)
We multiply parentheses
x^2-4x
Back to the equation:
-(x^2-4x)
x^2-x^2-4x+2x-2x+4x-8+8=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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