(x+2)(x-4)=(x-2)(x+1)

Solution for (x+2)(x-4)=(x-2)(x+1) equation:

(x+2)(x-4)=(x-2)(x+1)

We move all terms to the left:

(x+2)(x-4)-((x-2)(x+1))=0

We multiply parentheses ..

(+x^2-4x+2x-8)-((x-2)(x+1))=0


We calculate terms in parentheses: -((x-2)(x+1)), so:

(x-2)(x+1)

We multiply parentheses ..

(+x^2+x-2x-2)

We get rid of parentheses

x^2+x-2x-2

We add all the numbers together, and all the variables

x^2-1x-2

Back to the equation:

-(x^2-1x-2)


We get rid of parentheses

x^2-x^2-4x+2x+1x-8+2=0

We add all the numbers together, and all the variables

-1x-6=0

We move all terms containing x to the left, all other terms to the right

-x=6

x=6/-1

x=-6