(x+2)(x-4)=(x-2)(x+2)

Solution for (x+2)(x-4)=(x-2)(x+2) equation:

(x+2)(x-4)=(x-2)(x+2)

We move all terms to the left:

(x+2)(x-4)-((x-2)(x+2))=0

We use the square of the difference formula

x^2+(x+2)(x-4)+4=0

We multiply parentheses ..

x^2+(+x^2-4x+2x-8)+4=0

We get rid of parentheses

x^2+x^2-4x+2x-8+4=0

We add all the numbers together, and all the variables

2x^2-2x-4=0

a = 2; b = -2; c = -4;
Δ = b2-4ac
Δ = -22-4·2·(-4)
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-6}{2*2}=\frac{-4}{4}
=-1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+6}{2*2}=\frac{8}{4}
=2
$