(x+2)(x-4)=(x-2)(x=1)

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Solution for (x+2)(x-4)=(x-2)(x=1) equation: 



(x+2)(x-4)=(x-2)(x=1)

We move all terms to the left:

(x+2)(x-4)-((x-2)(x)=0

We multiply parentheses ..

(+x^2-4x+2x-8)-((x-2)x=0

We get rid of parentheses

x^2-4x+2x-((x-2)x-8=0

We add all the numbers together, and all the variables

x^2-2x-((x-2)x-8=0

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