(x+2)(x-5)=(x+3)(x-4)

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Solution for (x+2)(x-5)=(x+3)(x-4) equation: 



(x+2)(x-5)=(x+3)(x-4)

We move all terms to the left:

(x+2)(x-5)-((x+3)(x-4))=0

We multiply parentheses ..

(+x^2-5x+2x-10)-((x+3)(x-4))=0



We calculate terms in parentheses: -((x+3)(x-4)), so:

(x+3)(x-4)

We multiply parentheses ..

(+x^2-4x+3x-12)

We get rid of parentheses

x^2-4x+3x-12

We add all the numbers together, and all the variables

x^2-1x-12

Back to the equation:

-(x^2-1x-12)



We get rid of parentheses

x^2-x^2-5x+2x+1x-10+12=0

We add all the numbers together, and all the variables

-2x+2=0

We move all terms containing x to the left, all other terms to the right

-2x=-2

x=-2/-2

x=1

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