(x+2)(x-5)=6-3x

Solution for (x+2)(x-5)=6-3x equation:

Simplifying
(x + 2)(x + -5) = 6 + -3x

Reorder the terms:
(2 + x)(x + -5) = 6 + -3x

Reorder the terms:
(2 + x)(-5 + x) = 6 + -3x

Multiply (2 + x) * (-5 + x)
(2(-5 + x) + x(-5 + x)) = 6 + -3x
((-5 * 2 + x * 2) + x(-5 + x)) = 6 + -3x
((-10 + 2x) + x(-5 + x)) = 6 + -3x
(-10 + 2x + (-5 * x + x * x)) = 6 + -3x
(-10 + 2x + (-5x + x2)) = 6 + -3x

Combine like terms: 2x + -5x = -3x
(-10 + -3x + x2) = 6 + -3x

Add '3x' to each side of the equation.
-10 + -3x + 3x + x2 = 6 + -3x + 3x

Combine like terms: -3x + 3x = 0
-10 + 0 + x2 = 6 + -3x + 3x
-10 + x2 = 6 + -3x + 3x

Combine like terms: -3x + 3x = 0
-10 + x2 = 6 + 0
-10 + x2 = 6

Solving
-10 + x2 = 6

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '10' to each side of the equation.
-10 + 10 + x2 = 6 + 10

Combine like terms: -10 + 10 = 0
0 + x2 = 6 + 10
x2 = 6 + 10

Combine like terms: 6 + 10 = 16
x2 = 16

Simplifying
x2 = 16

Take the square root of each side:
x = {-4, 4}