(x+2)(x-6)=48

Solution for (x+2)(x-6)=48 equation:

(x+2)(x-6)=48

We move all terms to the left:

(x+2)(x-6)-(48)=0

We multiply parentheses ..

(+x^2-6x+2x-12)-48=0

We get rid of parentheses

x^2-6x+2x-12-48=0

We add all the numbers together, and all the variables

x^2-4x-60=0

a = 1; b = -4; c = -60;
Δ = b2-4ac
Δ = -42-4·1·(-60)
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{256}=16$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-16}{2*1}=\frac{-12}{2}
=-6
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+16}{2*1}=\frac{20}{2}
=10
$