(x+2)*(x-2)=(x+3)*(x-3)

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Solution for (x+2)*(x-2)=(x+3)*(x-3) equation: 



(x+2)(x-2)=(x+3)(x-3)

We move all terms to the left:

(x+2)(x-2)-((x+3)(x-3))=0

We use the square of the difference formula

x^2+x^2-4+9=0

We add all the numbers together, and all the variables

2x^2+5=0

a = 2; b = 0; c = +5;
Δ = b2-4ac
Δ = 02-4·2·5
Δ = -40
Delta is less than zero, so there is no solution for the equation

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