(x+2)*(x-3)+(x+3)*(x-2)=2*(x-2)*(x-3)

Solution for (x+2)*(x-3)+(x+3)*(x-2)=2*(x-2)*(x-3) equation:

(x+2)(x-3)+(x+3)(x-2)=2(x-2)(x-3)

We move all terms to the left:

(x+2)(x-3)+(x+3)(x-2)-(2(x-2)(x-3))=0

We multiply parentheses ..

(+x^2-3x+2x-6)+(x+3)(x-2)-(2(x-2)(x-3))=0


We calculate terms in parentheses: -(2(x-2)(x-3)), so:

2(x-2)(x-3)

We multiply parentheses ..

2(+x^2-3x-2x+6)

We multiply parentheses

2x^2-6x-4x+12

We add all the numbers together, and all the variables

2x^2-10x+12

Back to the equation:

-(2x^2-10x+12)


We get rid of parentheses

x^2-2x^2-3x+2x+(x+3)(x-2)+10x-6-12=0

We multiply parentheses ..

x^2-2x^2+(+x^2-2x+3x-6)-3x+2x+10x-6-12=0

We add all the numbers together, and all the variables

-1x^2+(+x^2-2x+3x-6)+9x-18=0

We get rid of parentheses

-1x^2+x^2-2x+3x+9x-6-18=0

We add all the numbers together, and all the variables

10x-24=0

We move all terms containing x to the left, all other terms to the right

10x=24

x=24/10

x=2+2/5