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(x+2)*x=483
We move all terms to the left:
(x+2)*x-(483)=0
We multiply parentheses
x^2+2x-483=0
a = 1; b = 2; c = -483;
Δ = b2-4ac
Δ = 22-4·1·(-483)
Δ = 1936
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1936}=44$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-44}{2*1}=\frac{-46}{2} =-23 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+44}{2*1}=\frac{42}{2} =21 $
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