(x+2)+(2x+1)+(3x-1)=0

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Solution for (x+2)+(2x+1)+(3x-1)=0 equation:


Simplifying
(x + 2) + (2x + 1) + (3x + -1) = 0

Reorder the terms:
(2 + x) + (2x + 1) + (3x + -1) = 0

Remove parenthesis around (2 + x)
2 + x + (2x + 1) + (3x + -1) = 0

Reorder the terms:
2 + x + (1 + 2x) + (3x + -1) = 0

Remove parenthesis around (1 + 2x)
2 + x + 1 + 2x + (3x + -1) = 0

Reorder the terms:
2 + x + 1 + 2x + (-1 + 3x) = 0

Remove parenthesis around (-1 + 3x)
2 + x + 1 + 2x + -1 + 3x = 0

Reorder the terms:
2 + 1 + -1 + x + 2x + 3x = 0

Combine like terms: 2 + 1 = 3
3 + -1 + x + 2x + 3x = 0

Combine like terms: 3 + -1 = 2
2 + x + 2x + 3x = 0

Combine like terms: x + 2x = 3x
2 + 3x + 3x = 0

Combine like terms: 3x + 3x = 6x
2 + 6x = 0

Solving
2 + 6x = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + 6x = 0 + -2

Combine like terms: 2 + -2 = 0
0 + 6x = 0 + -2
6x = 0 + -2

Combine like terms: 0 + -2 = -2
6x = -2

Divide each side by '6'.
x = -0.3333333333

Simplifying
x = -0.3333333333

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