(x+2)+(3x+1)+(x+7)=140

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Solution for (x+2)+(3x+1)+(x+7)=140 equation:


Simplifying
(x + 2) + (3x + 1) + (x + 7) = 140

Reorder the terms:
(2 + x) + (3x + 1) + (x + 7) = 140

Remove parenthesis around (2 + x)
2 + x + (3x + 1) + (x + 7) = 140

Reorder the terms:
2 + x + (1 + 3x) + (x + 7) = 140

Remove parenthesis around (1 + 3x)
2 + x + 1 + 3x + (x + 7) = 140

Reorder the terms:
2 + x + 1 + 3x + (7 + x) = 140

Remove parenthesis around (7 + x)
2 + x + 1 + 3x + 7 + x = 140

Reorder the terms:
2 + 1 + 7 + x + 3x + x = 140

Combine like terms: 2 + 1 = 3
3 + 7 + x + 3x + x = 140

Combine like terms: 3 + 7 = 10
10 + x + 3x + x = 140

Combine like terms: x + 3x = 4x
10 + 4x + x = 140

Combine like terms: 4x + x = 5x
10 + 5x = 140

Solving
10 + 5x = 140

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-10' to each side of the equation.
10 + -10 + 5x = 140 + -10

Combine like terms: 10 + -10 = 0
0 + 5x = 140 + -10
5x = 140 + -10

Combine like terms: 140 + -10 = 130
5x = 130

Divide each side by '5'.
x = 26

Simplifying
x = 26

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