(x+2)+(x+2)+(4x-4)=

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Solution for (x+2)+(x+2)+(4x-4)= equation:


Simplifying
(x + 2) + (x + 2) + (4x + -4) = 0

Reorder the terms:
(2 + x) + (x + 2) + (4x + -4) = 0

Remove parenthesis around (2 + x)
2 + x + (x + 2) + (4x + -4) = 0

Reorder the terms:
2 + x + (2 + x) + (4x + -4) = 0

Remove parenthesis around (2 + x)
2 + x + 2 + x + (4x + -4) = 0

Reorder the terms:
2 + x + 2 + x + (-4 + 4x) = 0

Remove parenthesis around (-4 + 4x)
2 + x + 2 + x + -4 + 4x = 0

Reorder the terms:
2 + 2 + -4 + x + x + 4x = 0

Combine like terms: 2 + 2 = 4
4 + -4 + x + x + 4x = 0

Combine like terms: 4 + -4 = 0
0 + x + x + 4x = 0
x + x + 4x = 0

Combine like terms: x + x = 2x
2x + 4x = 0

Combine like terms: 2x + 4x = 6x
6x = 0

Solving
6x = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Divide each side by '6'.
x = 0

Simplifying
x = 0

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