(x+2)+(x+3)+(x+3)=(x+2)+(x+2)+x+(x+2)

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Solution for (x+2)+(x+3)+(x+3)=(x+2)+(x+2)+x+(x+2) equation: 



(x+2)+(x+3)+(x+3)=(x+2)+(x+2)+x+(x+2)

We move all terms to the left:

(x+2)+(x+3)+(x+3)-((x+2)+(x+2)+x+(x+2))=0

We get rid of parentheses

x+x+x-((x+2)+(x+2)+x+(x+2))+2+3+3=0



We calculate terms in parentheses: -((x+2)+(x+2)+x+(x+2)), so:

(x+2)+(x+2)+x+(x+2)

We add all the numbers together, and all the variables

x+(x+2)+(x+2)+(x+2)

We get rid of parentheses

x+x+x+x+2+2+2

We add all the numbers together, and all the variables

4x+6

Back to the equation:

-(4x+6)



We add all the numbers together, and all the variables

3x-(4x+6)+8=0

We get rid of parentheses

3x-4x-6+8=0

We add all the numbers together, and all the variables

-1x+2=0

We move all terms containing x to the left, all other terms to the right

-x=-2

x=-2/-1

x=+2

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