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(x+2)+2=2(x+6)+4x
We move all terms to the left:
(x+2)+2-(2(x+6)+4x)=0
We get rid of parentheses
x-(2(x+6)+4x)+2+2=0
We calculate terms in parentheses: -(2(x+6)+4x), so:We add all the numbers together, and all the variables
2(x+6)+4x
We add all the numbers together, and all the variables
4x+2(x+6)
We multiply parentheses
4x+2x+12
We add all the numbers together, and all the variables
6x+12
Back to the equation:
-(6x+12)
x-(6x+12)+4=0
We get rid of parentheses
x-6x-12+4=0
We add all the numbers together, and all the variables
-5x-8=0
We move all terms containing x to the left, all other terms to the right
-5x=8
x=8/-5
x=-1+3/5
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