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(x+2)+2x=5(2x-5)-x
We move all terms to the left:
(x+2)+2x-(5(2x-5)-x)=0
We add all the numbers together, and all the variables
2x+(x+2)-(5(2x-5)-x)=0
We get rid of parentheses
2x+x-(5(2x-5)-x)+2=0
We calculate terms in parentheses: -(5(2x-5)-x), so:We add all the numbers together, and all the variables
5(2x-5)-x
We add all the numbers together, and all the variables
-1x+5(2x-5)
We multiply parentheses
-1x+10x-25
We add all the numbers together, and all the variables
9x-25
Back to the equation:
-(9x-25)
3x-(9x-25)+2=0
We get rid of parentheses
3x-9x+25+2=0
We add all the numbers together, and all the variables
-6x+27=0
We move all terms containing x to the left, all other terms to the right
-6x=-27
x=-27/-6
x=4+1/2
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