(x+2)+3x=2(x+1)+1

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Solution for (x+2)+3x=2(x+1)+1 equation: 



(x+2)+3x=2(x+1)+1

We move all terms to the left:

(x+2)+3x-(2(x+1)+1)=0

We add all the numbers together, and all the variables

3x+(x+2)-(2(x+1)+1)=0

We get rid of parentheses

3x+x-(2(x+1)+1)+2=0



We calculate terms in parentheses: -(2(x+1)+1), so:

2(x+1)+1

We multiply parentheses

2x+2+1

We add all the numbers together, and all the variables

2x+3

Back to the equation:

-(2x+3)



We add all the numbers together, and all the variables

4x-(2x+3)+2=0

We get rid of parentheses

4x-2x-3+2=0

We add all the numbers together, and all the variables

2x-1=0

We move all terms containing x to the left, all other terms to the right

2x=1

x=1/2

x=1/2

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