(x+2)-15=7/8x

Solution for (x+2)-15=7/8x equation:

(x+2)-15=7/8x

We move all terms to the left:

(x+2)-15-(7/8x)=0


Domain of the equation: 8x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(x+2)-(+7/8x)-15=0

We get rid of parentheses

x-7/8x+2-15=0

We multiply all the terms by the denominator


x*8x+2*8x-15*8x-7=0

Wy multiply elements

8x^2+16x-120x-7=0

We add all the numbers together, and all the variables

8x^2-104x-7=0

a = 8; b = -104; c = -7;
Δ = b2-4ac
Δ = -1042-4·8·(-7)
Δ = 11040
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{11040}=\sqrt{16*690}=\sqrt{16}*\sqrt{690}=4\sqrt{690}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-104)-4\sqrt{690}}{2*8}=\frac{104-4\sqrt{690}}{16}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-104)+4\sqrt{690}}{2*8}=\frac{104+4\sqrt{690}}{16}
$