(x+2)-2(2-5x)=6(x+5)-2

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Solution for (x+2)-2(2-5x)=6(x+5)-2 equation: 



(x+2)-2(2-5x)=6(x+5)-2

We move all terms to the left:

(x+2)-2(2-5x)-(6(x+5)-2)=0

We add all the numbers together, and all the variables

(x+2)-2(-5x+2)-(6(x+5)-2)=0

We multiply parentheses

(x+2)+10x-(6(x+5)-2)-4=0

We get rid of parentheses

x+10x-(6(x+5)-2)+2-4=0



We calculate terms in parentheses: -(6(x+5)-2), so:

6(x+5)-2

We multiply parentheses

6x+30-2

We add all the numbers together, and all the variables

6x+28

Back to the equation:

-(6x+28)



We add all the numbers together, and all the variables

11x-(6x+28)-2=0

We get rid of parentheses

11x-6x-28-2=0

We add all the numbers together, and all the variables

5x-30=0

We move all terms containing x to the left, all other terms to the right

5x=30

x=30/5

x=6

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