(x+2)-3(x-4)=6

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Solution for (x+2)-3(x-4)=6 equation:



(x+2)-3(x-4)=6
We move all terms to the left:
(x+2)-3(x-4)-(6)=0
We multiply parentheses
(x+2)-3x+12-6=0
We get rid of parentheses
x-3x+2+12-6=0
We add all the numbers together, and all the variables
-2x+8=0
We move all terms containing x to the left, all other terms to the right
-2x=-8
x=-8/-2
x=+4

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