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(x+2)/(x-5)=3/10
We move all terms to the left:
(x+2)/(x-5)-(3/10)=0
Domain of the equation: (x-5)!=0We add all the numbers together, and all the variables
We move all terms containing x to the left, all other terms to the right
x!=5
x∈R
(x+2)/(x-5)-(+3/10)=0
We get rid of parentheses
(x+2)/(x-5)-3/10=0
We calculate fractions
(10x+20)/(10x-50)+(-3x+15)/(10x-50)=0
We multiply all the terms by the denominator
(10x+20)+(-3x+15)=0
We get rid of parentheses
10x-3x+20+15=0
We add all the numbers together, and all the variables
7x+35=0
We move all terms containing x to the left, all other terms to the right
7x=-35
x=-35/7
x=-5
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