(x+2)/15=(x+1)/5

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Solution for (x+2)/15=(x+1)/5 equation: 



(x+2)/15=(x+1)/5

We move all terms to the left:

(x+2)/15-((x+1)/5)=0

We calculate fractions


x/()+(-((x+1)*15)/()=0



We calculate terms in parentheses: +(-((x+1)*15)/(), so:

-((x+1)*15)/(

We multiply all the terms by the denominator


-((x+1)*15)



We calculate terms in parentheses: -((x+1)*15), so:

(x+1)*15

We multiply parentheses

15x+15

Back to the equation:

-(15x+15)



We get rid of parentheses

-15x-15

Back to the equation:

+(-15x-15)



We get rid of parentheses

x/()-15x-15=0

We multiply all the terms by the denominator


x-15x*()-15*()=0

We add all the numbers together, and all the variables

x-15x*()=0

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