(x+2)/2=8-(x+1)/3

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Solution for (x+2)/2=8-(x+1)/3 equation: 



(x+2)/2=8-(x+1)/3

We move all terms to the left:

(x+2)/2-(8-(x+1)/3)=0

We calculate fractions


x/()+(-(8-(x+1)*2)/()=0



We calculate terms in parentheses: +(-(8-(x+1)*2)/(), so:

-(8-(x+1)*2)/(

We multiply all the terms by the denominator


-(8-(x+1)*2)



We calculate terms in parentheses: -(8-(x+1)*2), so:

8-(x+1)*2

determiningTheFunctionDomain
-(x+1)*2+8

We multiply parentheses

-2x-2+8

We add all the numbers together, and all the variables

-2x+6

Back to the equation:

-(-2x+6)



We get rid of parentheses

2x-6

Back to the equation:

+(2x-6)



We get rid of parentheses

x/()+2x-6=0

We multiply all the terms by the denominator


x+2x*()-6*()=0

We add all the numbers together, and all the variables

x+2x*()=0

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