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(x+2)/3-(x-5)-4=2
We move all terms to the left:
(x+2)/3-(x-5)-4-(2)=0
We add all the numbers together, and all the variables
(x+2)/3-(x-5)-6=0
We get rid of parentheses
(x+2)/3-x+5-6=0
We multiply all the terms by the denominator
(x+2)-x*3+5*3-6*3=0
We add all the numbers together, and all the variables
(x+2)-x*3-3=0
Wy multiply elements
(x+2)-3x-3=0
We get rid of parentheses
x-3x+2-3=0
We add all the numbers together, and all the variables
-2x-1=0
We move all terms containing x to the left, all other terms to the right
-2x=1
x=1/-2
x=-1/2
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