(x+2)/3=(2x+1)/5

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Solution for (x+2)/3=(2x+1)/5 equation: 


x in (-oo:+oo)

(x+2)/3 = (2*x+1)/5 // - (2*x+1)/5

(x+2)/3-((2*x+1)/5) = 0

(x+2)/3+(-1*(2*x+1))/5 = 0

(5*(x+2))/(3*5)+(-1*3*(2*x+1))/(3*5) = 0

5*(x+2)-1*3*(2*x+1) = 0

7-x = 0

(7-x)/(3*5) = 0

(7-x)/(3*5) = 0 // * 3*5

7-x = 0

7-x = 0 // - 7

-x = -7 // * -1

x = 7

x = 7

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