(x+2)/3=(2x-4)/2

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Solution for (x+2)/3=(2x-4)/2 equation: 



(x+2)/3=(2x-4)/2

We move all terms to the left:

(x+2)/3-((2x-4)/2)=0

We calculate fractions


x/()+(-((2x-4)*3)/()=0



We calculate terms in parentheses: +(-((2x-4)*3)/(), so:

-((2x-4)*3)/(

We multiply all the terms by the denominator


-((2x-4)*3)



We calculate terms in parentheses: -((2x-4)*3), so:

(2x-4)*3

We multiply parentheses

6x-12

Back to the equation:

-(6x-12)



We get rid of parentheses

-6x+12

Back to the equation:

+(-6x+12)



We get rid of parentheses

x/()-6x+12=0

We multiply all the terms by the denominator


x-6x*()+12*()=0

We add all the numbers together, and all the variables

x-6x*()=0

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