(x+2)/3=(x-2)/7

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Solution for (x+2)/3=(x-2)/7 equation: 



(x+2)/3=(x-2)/7

We move all terms to the left:

(x+2)/3-((x-2)/7)=0

We calculate fractions


x/()+(-((x-2)*3)/()=0



We calculate terms in parentheses: +(-((x-2)*3)/(), so:

-((x-2)*3)/(

We multiply all the terms by the denominator


-((x-2)*3)



We calculate terms in parentheses: -((x-2)*3), so:

(x-2)*3

We multiply parentheses

3x-6

Back to the equation:

-(3x-6)



We get rid of parentheses

-3x+6

Back to the equation:

+(-3x+6)



We get rid of parentheses

x/()-3x+6=0

We multiply all the terms by the denominator


x-3x*()+6*()=0

We add all the numbers together, and all the variables

x-3x*()=0

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