(x+2)/3=(x-4)/5

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Solution for (x+2)/3=(x-4)/5 equation: 



(x+2)/3=(x-4)/5

We move all terms to the left:

(x+2)/3-((x-4)/5)=0

We calculate fractions


x/()+(-((x-4)*3)/()=0



We calculate terms in parentheses: +(-((x-4)*3)/(), so:

-((x-4)*3)/(

We multiply all the terms by the denominator


-((x-4)*3)



We calculate terms in parentheses: -((x-4)*3), so:

(x-4)*3

We multiply parentheses

3x-12

Back to the equation:

-(3x-12)



We get rid of parentheses

-3x+12

Back to the equation:

+(-3x+12)



We get rid of parentheses

x/()-3x+12=0

We multiply all the terms by the denominator


x-3x*()+12*()=0

We add all the numbers together, and all the variables

x-3x*()=0

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