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(x+2)/4=(3x+3)/8
We move all terms to the left:
(x+2)/4-((3x+3)/8)=0
We calculate fractions
x/()+(-((3x+3)*4)/()=0
We calculate terms in parentheses: +(-((3x+3)*4)/(), so:We get rid of parentheses
-((3x+3)*4)/(
We multiply all the terms by the denominator
-((3x+3)*4)
We calculate terms in parentheses: -((3x+3)*4), so:We get rid of parentheses
(3x+3)*4
We multiply parentheses
12x+12
Back to the equation:
-(12x+12)
-12x-12
Back to the equation:
+(-12x-12)
x/()-12x-12=0
We multiply all the terms by the denominator
x-12x*()-12*()=0
We add all the numbers together, and all the variables
x-12x*()=0
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