(x+2)/4=(3x+3)/8

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Solution for (x+2)/4=(3x+3)/8 equation: 



(x+2)/4=(3x+3)/8

We move all terms to the left:

(x+2)/4-((3x+3)/8)=0

We calculate fractions


x/()+(-((3x+3)*4)/()=0



We calculate terms in parentheses: +(-((3x+3)*4)/(), so:

-((3x+3)*4)/(

We multiply all the terms by the denominator


-((3x+3)*4)



We calculate terms in parentheses: -((3x+3)*4), so:

(3x+3)*4

We multiply parentheses

12x+12

Back to the equation:

-(12x+12)



We get rid of parentheses

-12x-12

Back to the equation:

+(-12x-12)



We get rid of parentheses

x/()-12x-12=0

We multiply all the terms by the denominator


x-12x*()-12*()=0

We add all the numbers together, and all the variables

x-12x*()=0

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