(x+2)/4=(x-3)/5

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Solution for (x+2)/4=(x-3)/5 equation: 



(x+2)/4=(x-3)/5

We move all terms to the left:

(x+2)/4-((x-3)/5)=0

We calculate fractions


x/()+(-((x-3)*4)/()=0



We calculate terms in parentheses: +(-((x-3)*4)/(), so:

-((x-3)*4)/(

We multiply all the terms by the denominator


-((x-3)*4)



We calculate terms in parentheses: -((x-3)*4), so:

(x-3)*4

We multiply parentheses

4x-12

Back to the equation:

-(4x-12)



We get rid of parentheses

-4x+12

Back to the equation:

+(-4x+12)



We get rid of parentheses

x/()-4x+12=0

We multiply all the terms by the denominator


x-4x*()+12*()=0

We add all the numbers together, and all the variables

x-4x*()=0

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