(x+2)/5=(10-2x)/3

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Solution for (x+2)/5=(10-2x)/3 equation: 



(x+2)/5=(10-2x)/3

We move all terms to the left:

(x+2)/5-((10-2x)/3)=0

We add all the numbers together, and all the variables

(x+2)/5-((-2x+10)/3)=0

We calculate fractions


x/()+(-((-2x+10)*5)/()=0



We calculate terms in parentheses: +(-((-2x+10)*5)/(), so:

-((-2x+10)*5)/(

We multiply all the terms by the denominator


-((-2x+10)*5)



We calculate terms in parentheses: -((-2x+10)*5), so:

(-2x+10)*5

We multiply parentheses

-10x+50

Back to the equation:

-(-10x+50)



We get rid of parentheses

10x-50

Back to the equation:

+(10x-50)



We get rid of parentheses

x/()+10x-50=0

We multiply all the terms by the denominator


x+10x*()-50*()=0

We add all the numbers together, and all the variables

x+10x*()=0

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