(x+2)/5=1-(x+6)/7

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Solution for (x+2)/5=1-(x+6)/7 equation: 



(x+2)/5=1-(x+6)/7

We move all terms to the left:

(x+2)/5-(1-(x+6)/7)=0

We calculate fractions


x/()+(-(1-(x+6)*5)/()=0



We calculate terms in parentheses: +(-(1-(x+6)*5)/(), so:

-(1-(x+6)*5)/(

We multiply all the terms by the denominator


-(1-(x+6)*5)



We calculate terms in parentheses: -(1-(x+6)*5), so:

1-(x+6)*5

determiningTheFunctionDomain
-(x+6)*5+1

We multiply parentheses

-5x-30+1

We add all the numbers together, and all the variables

-5x-29

Back to the equation:

-(-5x-29)



We get rid of parentheses

5x+29

Back to the equation:

+(5x+29)



We get rid of parentheses

x/()+5x+29=0

We multiply all the terms by the denominator


x+5x*()+29*()=0

We add all the numbers together, and all the variables

x+5x*()=0

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