(x+2)/6=(2x-10)/8

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Solution for (x+2)/6=(2x-10)/8 equation: 



(x+2)/6=(2x-10)/8

We move all terms to the left:

(x+2)/6-((2x-10)/8)=0

We calculate fractions


x/()+(-((2x-10)*6)/()=0



We calculate terms in parentheses: +(-((2x-10)*6)/(), so:

-((2x-10)*6)/(

We multiply all the terms by the denominator


-((2x-10)*6)



We calculate terms in parentheses: -((2x-10)*6), so:

(2x-10)*6

We multiply parentheses

12x-60

Back to the equation:

-(12x-60)



We get rid of parentheses

-12x+60

Back to the equation:

+(-12x+60)



We get rid of parentheses

x/()-12x+60=0

We multiply all the terms by the denominator


x-12x*()+60*()=0

We add all the numbers together, and all the variables

x-12x*()=0

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