(x+2)/6=x-3

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Solution for (x+2)/6=x-3 equation: 



(x+2)/6=x-3

We move all terms to the left:

(x+2)/6-(x-3)=0

We get rid of parentheses

(x+2)/6-x+3=0

We multiply all the terms by the denominator


(x+2)-x*6+3*6=0

We add all the numbers together, and all the variables

(x+2)-x*6+18=0

Wy multiply elements

(x+2)-6x+18=0

We get rid of parentheses

x-6x+2+18=0

We add all the numbers together, and all the variables

-5x+20=0

We move all terms containing x to the left, all other terms to the right

-5x=-20

x=-20/-5

x=+4

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