(x+2)/8=2(x+1)-28

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Solution for (x+2)/8=2(x+1)-28 equation: 



(x+2)/8=2(x+1)-28

We move all terms to the left:

(x+2)/8-(2(x+1)-28)=0

We multiply all the terms by the denominator


(x+2)-((2(x+1)-28))*8=0

We get rid of parentheses

x-((2(x+1)-28))*8+2=0

We move all terms containing x to the left, all other terms to the right

x-((2(x+1)-28))*8=-2

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