(x+2)2+(y+1)2=32

Solution for (x+2)2+(y+1)2=32 equation:

Simplifying
(x + 2) * 2 + (y + 1) * 2 = 32

Reorder the terms:
(2 + x) * 2 + (y + 1) * 2 = 32

Reorder the terms for easier multiplication:
2(2 + x) + (y + 1) * 2 = 32
(2 * 2 + x * 2) + (y + 1) * 2 = 32
(4 + 2x) + (y + 1) * 2 = 32

Reorder the terms:
4 + 2x + (1 + y) * 2 = 32

Reorder the terms for easier multiplication:
4 + 2x + 2(1 + y) = 32
4 + 2x + (1 * 2 + y * 2) = 32
4 + 2x + (2 + 2y) = 32

Reorder the terms:
4 + 2 + 2x + 2y = 32

Combine like terms: 4 + 2 = 6
6 + 2x + 2y = 32

Solving
6 + 2x + 2y = 32

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-6' to each side of the equation.
6 + 2x + -6 + 2y = 32 + -6

Reorder the terms:
6 + -6 + 2x + 2y = 32 + -6

Combine like terms: 6 + -6 = 0
0 + 2x + 2y = 32 + -6
2x + 2y = 32 + -6

Combine like terms: 32 + -6 = 26
2x + 2y = 26

Add '-2y' to each side of the equation.
2x + 2y + -2y = 26 + -2y

Combine like terms: 2y + -2y = 0
2x + 0 = 26 + -2y
2x = 26 + -2y

Divide each side by '2'.
x = 13 + -1y

Simplifying
x = 13 + -1y