(x+2)2=(x-2)(x+2)

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Solution for (x+2)2=(x-2)(x+2) equation: 



(x+2)2=(x-2)(x+2)

We move all terms to the left:

(x+2)2-((x-2)(x+2))=0

We use the square of the difference formula

x^2+(x+2)2+4=0

We multiply parentheses

x^2+2x+4+4=0

We add all the numbers together, and all the variables

x^2+2x+8=0

a = 1; b = 2; c = +8;
Δ = b2-4ac
Δ = 22-4·1·8
Δ = -28
Delta is less than zero, so there is no solution for the equation

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